Calculate the force of attraction between two balls each of mass 1kg w – McqOptions

MCQOPTIONS

1.	Calculate the force of attraction between two balls each of mass 1kg when their centres are 10cm apart. The value of gravitational constant G = 6.67‚Äö√†√∂‚àö‚â•10^-11 Nm² kg^(-2).$
A.	6.67‚Äö√†√∂‚àö‚â•10<sup>-11</sup>N
B.	6.67‚Äö√†√∂‚àö‚â•10<sup>-10</sup>N
C.	6.67N
D.	6.67‚Äö√†√∂‚àö‚â•10<sup>10</sup> N
Answer» C. 6.67N

Discussion

No Comment Found

Related MCQs

What is the ration of the force of attraction between two bodies kept in the air and the same distance apart in the water?
G is called gravitation constant.
A ball dropped from a spacecraft is revolving around the earth at a height of 120km. What will happen to the ball?
Imagine a new planet having the same density as that of earth but it is 3 times bigger than the earth in its size. If the acceleration due to gravity on the surface of the earth is g and that on the surface of the new planet g‘ is?
Statement 1 – If a pendulum falls freely, then its time period is infinite.Statement 2 – Free falling body has acceleration equal to g.
Statement 1 – The earth is slowing down and as a result, the moon is coming nearer to it.Statement 2 – The angular momentum of the system is not conserved.
If the kinetic energy of the satellite revolving in an orbit close to the earth’s surface happens to be doubled, what happens to the satellite?
Calculate the force of attraction between two balls each of mass 1kg when their centres are 10cm apart. The value of gravitational constant G = 6.67×10-11 Nm2 kg(-2).
A_BALL_DROPPED_FROM_A_SPACECRAFT_IS_REVOLVING_AROUND_THE_EARTH_AT_A_HEIGHT_OF_120KM._WHAT_WILL_HAPPEN_TO_THE_BALL??$
What is the ration of the force of attraction between two bodies kept in the air and the same distance apart in water?$