\[C{{H}_{3}}-C{{H}_{2}}C\equiv N\xrightarrow{X}C{{H}_{3}}C{{H}_{2}}CHO\]. The compound X is

\[SnC{{l}_{2}}/HCl/{{H}_{2}}O,boil\]

\[NaB{{H}_{4}}/ether/{{H}_{3}}{{O}^{+}}\]

\[C{{H}_{3}}-C{{H}_{2}}C\equiv N\xrightarrow{X}C{{H}_{3}}C{{H}_{2}}CHO

1.	\[C{{H}_{3}}-C{{H}_{2}}C\equiv N\xrightarrow{X}C{{H}_{3}}C{{H}_{2}}CHO\]. The compound X is
A.	\[SnC{{l}_{2}}/HCl/{{H}_{2}}O,boil\]
B.	\[{{H}_{2}}/Pd-BaS{{O}_{4}}\]
C.	\[LiAI{{H}_{4}}/ether\]
D.	\[NaB{{H}_{4}}/ether/{{H}_{3}}{{O}^{+}}\]
Answer» B. \[{{H}_{2}}/Pd-BaS{{O}_{4}}\]

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\[C{{H}_{3}}-C{{H}_{2}}C\equiv N\xrightarrow{X}C{{H}_{3}}C{{H}_{2}}CHO\]. The compound X is

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