\[{{C}_{2}}{{H}_{5}}Br\xrightarrow{AgCN}X\xrightarrow[Zn-Hg/HCl]{Reduc – McqOptions

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1.	\[{{C}_{2}}{{H}_{5}}Br\xrightarrow{AgCN}X\xrightarrow[Zn-Hg/HCl]{Reduction}Y,Here\] Y is
A.	Ethyl methyl amine
B.	n-propylamine
C.	Isopropylamine
D.	Ethylamine
Answer» B. n-propylamine

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