Bond distance in HF is \[~9.17\times {{10}^{-11}}m.\] Dipole moment of HF is \[6.104\times {{10}^{-30}}Cm.\] The percentage ionic character in HF will be: (electron charge\[=1.60\times {{10}^{-19}}C\])

Bond distance in HF is \[~9.17\times {{10}^{-11}}m.\] Dipole moment of

1.	Bond distance in HF is \[~9.17\times {{10}^{-11}}m.\] Dipole moment of HF is \[6.104\times {{10}^{-30}}Cm.\] The percentage ionic character in HF will be: (electron charge\[=1.60\times {{10}^{-19}}C\])
A.	61.0%
B.	0.38
C.	35.5%
D.	0.415
Answer» E.

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Bond distance in HF is \[~9.17\times {{10}^{-11}}m.\] Dipole moment of HF is \[6.104\times {{10}^{-30}}Cm.\] The percentage ionic character in HF will be: (electron charge\[=1.60\times {{10}^{-19}}C\])

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