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1. |
Based on the equal deflection criterion, the expression for the equivalent wheel load Pₑ is _________ |
A. | \(F_e \sqrt{P_e}=(F_1+F_2)\sqrt{P} \) |
B. | \(F_e \sqrt{P_e}=(F_1-F_2) \sqrt{P}\) |
C. | \(F_e \sqrt{P_e}=(F_1*F_2) \sqrt{P}\) |
D. | \(F_e \sqrt{P_e}=(F_1/F_2) \sqrt{P}\) |
Answer» B. \(F_e \sqrt{P_e}=(F_1-F_2) \sqrt{P}\) | |