1.

Based on the equal deflection criterion, the expression for the equivalent wheel load Pₑ is _________

A. \(F_e \sqrt{P_e}=(F_1+F_2)\sqrt{P} \)
B. \(F_e \sqrt{P_e}=(F_1-F_2) \sqrt{P}\)
C. \(F_e \sqrt{P_e}=(F_1*F_2) \sqrt{P}\)
D. \(F_e \sqrt{P_e}=(F_1/F_2) \sqrt{P}\)
Answer» B. \(F_e \sqrt{P_e}=(F_1-F_2) \sqrt{P}\)


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