Average of n numbers is a. The first number is increased by 2, second one is increased by 4, the third one is increased by 8 and so on. The average of the new numbers is -

$a + \frac{{{2^{n + 1}} - 1}}{n}$$

$a + \frac{{2\left( {{2^n} - 1} \right)}}{n}$$

$a + 2\frac{{{2^{n - 1}}}}{n}$$

Average of n numbers is a. The first number is increased by 2, second

1.	Average of n numbers is a. The first number is increased by 2, second one is increased by 4, the third one is increased by 8 and so on. The average of the new numbers is -
A.	$a + \frac{{2\left( {{2^n} - 1} \right)}}{n}$$
B.	$a + \frac{{{2^{n + 1}} - 1}}{n}$$
C.	$a + \frac{{{2^{n + 1}}}}{n}$$
D.	$a + 2\frac{{{2^{n - 1}}}}{n}$$
Answer» B. $a + \frac{{{2^{n + 1}} - 1}}{n}$$

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Average of n numbers is a. The first number is increased by 2, second one is increased by 4, the third one is increased by 8 and so on. The average of the new numbers is -

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