At t=0, the shape of a travelling pulse is given by $$y(x,0)=\frac{4\times {{10}^{-3}}}{8\times {{(x)}^{-2}}}$$ where x and y are in metres. The wave function for the travelling pulse if the velocity or propagation is 5 m/s in the x direction is given by

Question

TuteeHUB · Accepted Answer

$$y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x+5t)}^{2}}}$$

TuteeHUB · Answer

$$y(x,t)=\frac{4\times {{10}^{-3}}}{8-({{x}^{2}}-5t)}$$

TuteeHUB · Answer

$$y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x-5t)}^{2}}}$$

TuteeHUB · Answer

$$y(x,t)=\frac{4\times {{10}^{-3}}}{8-({{x}^{2}}+5t)}$$

1.	At t=0, the shape of a travelling pulse is given by \[y(x,0)=\frac{4\times {{10}^{-3}}}{8\times {{(x)}^{-2}}}\] where x and y are in metres. The wave function for the travelling pulse if the velocity or propagation is 5 m/s in the x direction is given by
A.	\[y(x,t)=\frac{4\times {{10}^{-3}}}{8-({{x}^{2}}-5t)}\]
B.	\[y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x-5t)}^{2}}}\]
C.	\[y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x+5t)}^{2}}}\]
D.	\[y(x,t)=\frac{4\times {{10}^{-3}}}{8-({{x}^{2}}+5t)}\]
Answer» C. \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x+5t)}^{2}}}\]

At t=0, the shape of a travelling pulse is given by \[y(x,0)=\frac{4\times {{10}^{-3}}}{8\times {{(x)}^{-2}}}\] where x and y are in metres. The wave function for the travelling pulse if the velocity or propagation is 5 m/s in the x direction is given by

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