MCQOPTIONS
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| 1. |
At a place on earth, horizontal component of earth's magnetic field is \[{{B}_{1}}\] and vertical component of earth's magnetic field is \[{{B}_{2}}\]. If a magnetic needle is kept vertical, in a plane making angle \[\alpha \] with the horizontal component of magnetic field, then square of time period of oscillation of needle when slightly distributed is proportional to |
| A. | \[\frac{1}{\sqrt{{{B}_{1}}\,\cos \,\alpha }}\] |
| B. | \[\frac{1}{\sqrt{{{B}_{2}}}}\] |
| C. | \[\frac{1}{\sqrt{{{({{B}_{1\,}}\cos \,\alpha )}^{2}}+B_{2}^{2}}}\] |
| D. | infinite |
| Answer» D. infinite | |