As per this diagram a point charge +q is placed at the origin O. Work done in taking another point chargeQ from the point A [co-ordinates $$(0,\,\,a)$$] to another points [co-ordinates $$(a,\text{ }0)$$] along the straight path AB is: [AIPMT (S) 2005]

Question

As per this diagram a point charge +q is placed at the origin O. Work done in taking another point chargeQ  from the point A [co-ordinates $$(0,\,\,a)$$] to another points [co-ordinates $$(a,\text{ }0)$$] along the straight path AB is:                  [AIPMT (S) 2005]

TuteeHUB · Accepted Answer

$$\left( \frac{-qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\sqrt{2}a$$

TuteeHUB · Answer

zero

TuteeHUB · Answer

$$\left( \frac{qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\cdot \frac{a}{\sqrt{2}}$$

TuteeHUB · Answer

$$\left( \frac{qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\sqrt{2}a$$

1.	As per this diagram a point charge +q is placed at the origin O. Work done in taking another point chargeQ from the point A [co-ordinates \[(0,\,\,a)\]] to another points [co-ordinates \[(a,\text{ }0)\]] along the straight path AB is: [AIPMT (S) 2005]
A.	zero
B.	\[\left( \frac{-qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\sqrt{2}a\]
C.	\[\left( \frac{qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\cdot \frac{a}{\sqrt{2}}\]
D.	\[\left( \frac{qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\sqrt{2}a\]
Answer» B. \[\left( \frac{-qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\sqrt{2}a\]

As per this diagram a point charge +q is placed at the origin O. Work done in taking another point chargeQ from the point A [co-ordinates \[(0,\,\,a)\]] to another points [co-ordinates \[(a,\text{ }0)\]] along the straight path AB is: [AIPMT (S) 2005]

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