As per the diagram, a point charge +q is placed at the origin O. Work done in taking another point charge-Q from the point A [coordinates (0, a)] to another point B [coordinates (a, 0)] along the straight path AB is:

\[\left( \frac{-qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\sqrt{2}a\]

\[\left( \frac{-qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right).\frac{a}{\sqrt{2}}\]

\[\left( \frac{qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right).\sqrt{2}a\]

As per the diagram, a point charge +q is placed at the origin O. Work

1.	As per the diagram, a point charge +q is placed at the origin O. Work done in taking another point charge-Q from the point A [coordinates (0, a)] to another point B [coordinates (a, 0)] along the straight path AB is:
A.	zero
B.	\[\left( \frac{-qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\sqrt{2}a\]
C.	\[\left( \frac{-qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right).\frac{a}{\sqrt{2}}\]
D.	\[\left( \frac{qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right).\sqrt{2}a\]
Answer» B. \[\left( \frac{-qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{a}^{2}}} \right)\sqrt{2}a\]