1.

Arrange the given steps in CORRECT order, while constructing \[\Delta \,PQR\]where \[PM\bot QS\]and it is given that \[QR=4.2\text{ }cm,\]\[\angle Q={{120}^{o}}\] and \[PQ=3.5\text{ }cm.\] Step 1. Now, extend RQ to S and with P as centre and with a sufficient radius, draw an arc, cutting SO at A and 8.           Step 2. Along QX, set off \[QP=3.5\text{ }cm.\] Step 3. Draw a line segment \[QR=4.2\text{ }cm\]and construct\[\angle RQX={{120}^{o}}\]. Step 4. Joint PR. Step 5. Joint PC, meeting RQ product at M. Then. \[PM\bot QS\] Step 6. With A as centre and radius more than half AB, draw an arc. Now with B as centre and with the same radius draw another arc, cutting the previous arc at C.

A.  1\[\to \]2\[\to \]3\[\to \]4\[\to \]5\[\to \]6
B.  4\[\to \]1\[\to \]2\[\to \]3\[\to \]5\[\to \]6          
C.  2\[\to \]4\[\to \]3\[\to \]1\[\to \]5\[\to \]6          
D.  3\[\to \]2\[\to \]4\[\to \]1\[\to \]6\[\to \]5          
Answer» E.


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