\[arg\left( \frac{3+i}{2-i}+\frac{3-i}{2+i} \right)\] is equal to

1.	\[arg\left( \frac{3+i}{2-i}+\frac{3-i}{2+i} \right)\] is equal to
A.	\[\frac{\pi }{2}\]
B.	\[-\frac{\pi }{2}\]
C.	0
D.	\[\frac{\pi }{4}\]
Answer» D. \[\frac{\pi }{4}\]

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\[arg\left( \frac{3+i}{2-i}+\frac{3-i}{2+i} \right)\] is equal to

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