Angle between the line \[\mathbf{r}=(2\mathbf{i}-\mathbf{j}+\mathbf{k})+\lambda (-\mathbf{i}+\mathbf{j}+\mathbf{k})\] and the plane \[\mathbf{r}.(3\mathbf{i}+2\mathbf{j}-\mathbf{k})=4\] is

\[{{\cos }^{-1}}\left( \frac{2}{\sqrt{42}} \right)\]

\[{{\cos }^{-1}}\left( \frac{-2}{\sqrt{42}} \right)\]

\[{{\sin }^{-1}}\left( \frac{2}{\sqrt{42}} \right)\]

\[{{\sin }^{-1}}\left( \frac{-2}{\sqrt{42}} \right)\]

Angle between the line \[\mathbf{r}=(2\mathbf{i}-\mathbf{j}+\mathbf{k}

1.	Angle between the line \[\mathbf{r}=(2\mathbf{i}-\mathbf{j}+\mathbf{k})+\lambda (-\mathbf{i}+\mathbf{j}+\mathbf{k})\] and the plane \[\mathbf{r}.(3\mathbf{i}+2\mathbf{j}-\mathbf{k})=4\] is
A.	\[{{\cos }^{-1}}\left( \frac{2}{\sqrt{42}} \right)\]
B.	\[{{\cos }^{-1}}\left( \frac{-2}{\sqrt{42}} \right)\]
C.	\[{{\sin }^{-1}}\left( \frac{2}{\sqrt{42}} \right)\]
D.	\[{{\sin }^{-1}}\left( \frac{-2}{\sqrt{42}} \right)\]
Answer» E.

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Angle between the line \[\mathbf{r}=(2\mathbf{i}-\mathbf{j}+\mathbf{k})+\lambda (-\mathbf{i}+\mathbf{j}+\mathbf{k})\] and the plane \[\mathbf{r}.(3\mathbf{i}+2\mathbf{j}-\mathbf{k})=4\] is

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