1.

An X-ray machine has an accelerating potential difference of 25,000 volts. By calculation the shortest wavelength will be obtained as (\[h=6.62\times {{10}^{-34}}\] J?sec; e = \[1.6\times {{10}^{-19}}\]coulomb) [MP PET 1994]

A. 0.25 Å
B. 0.50 Å
C. 1.00 Å
D. 2.50 Å
Answer» C. 1.00 Å


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