MCQOPTIONS
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| 1. |
An X-ray machine has an accelerating potential difference of 25,000 volts. By calculation the shortest wavelength will be obtained as (\[h=6.62\times {{10}^{-34}}\] J?sec; e = \[1.6\times {{10}^{-19}}\]coulomb) [MP PET 1994] |
| A. | 0.25 Å |
| B. | 0.50 Å |
| C. | 1.00 Å |
| D. | 2.50 Å |
| Answer» C. 1.00 Å | |