An optically active alkyl bromide X (\[{{C}_{6}}{{H}_{13}}Br\]) upon treatment with ethanolic KOH solution forms two alkenes Y and Z with their molecular formula (\[{{C}_{6}}{{H}_{12}}\]). Y and Z are positional isomers. Z upon treatment with cold, dilute alkaline \[KMn{{O}_{4}}\] solution gives a meso-diol. Hence, X is

An optically active alkyl bromide X (\[{{C}_{6}}{{H}_{13}}Br\]) upon t

1.	An optically active alkyl bromide X (\[{{C}_{6}}{{H}_{13}}Br\]) upon treatment with ethanolic KOH solution forms two alkenes Y and Z with their molecular formula (\[{{C}_{6}}{{H}_{12}}\]). Y and Z are positional isomers. Z upon treatment with cold, dilute alkaline \[KMn{{O}_{4}}\] solution gives a meso-diol. Hence, X is
A.	2-bromohexane
B.	1-bromo-2, 3-dimethyl butane
C.	3-bromohexane
D.	2-bromo-2, 3-dimethyl butane
Answer» D. 2-bromo-2, 3-dimethyl butane

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