An open pipe is in resonance in its 2nd harmonic with tuning fork of frequency$${{f}_{1}}$$. Now it is closed at one end. If the frequency of the tuning fork is increased slowly from $${{f}_{1}}$$ then again a resonance is obtained with a frequency$${{f}_{2}}$$. If in this case the pipe vibrates $${{n}^{th}}$$ harmonics then [IIT-JEE (Screening) 2005]

Question

An open pipe is in resonance in its 2nd harmonic with tuning fork of frequency$${{f}_{1}}$$. Now it is closed at one end. If the frequency of the tuning fork is increased slowly from $${{f}_{1}}$$ then again a resonance is obtained with a frequency$${{f}_{2}}$$. If in this case the pipe vibrates $${{n}^{th}}$$ harmonics then  [IIT-JEE (Screening) 2005]

TuteeHUB · Accepted Answer

$$n=5,$$ $${{f}_{2}}=\frac{3}{4}{{f}_{1}}$$

TuteeHUB · Answer

$$n=3,$$ $${{f}_{2}}=\frac{3}{4}{{f}_{1}}$$

TuteeHUB · Answer

$$n=3,$$ $${{f}_{2}}=\frac{5}{4}{{f}_{1}}$$

TuteeHUB · Answer

$$n=5,$$ $${{f}_{2}}=\frac{5}{4}{{f}_{1}}$$

TuteeHUB · Answer

$$n=5,$$ $${{f}_{2}}=\frac{3}{4}{{f}_{1}}$$

1.	An open pipe is in resonance in its 2nd harmonic with tuning fork of frequency\[{{f}_{1}}\]. Now it is closed at one end. If the frequency of the tuning fork is increased slowly from \[{{f}_{1}}\] then again a resonance is obtained with a frequency\[{{f}_{2}}\]. If in this case the pipe vibrates \[{{n}^{th}}\] harmonics then [IIT-JEE (Screening) 2005]
A.	\[n=3,\] \[{{f}_{2}}=\frac{3}{4}{{f}_{1}}\]
B.	\[n=3,\] \[{{f}_{2}}=\frac{5}{4}{{f}_{1}}\]
C.	\[n=5,\] \[{{f}_{2}}=\frac{5}{4}{{f}_{1}}\]
D.	\[n=5,\] \[{{f}_{2}}=\frac{3}{4}{{f}_{1}}\]
Answer» D. \[n=5,\] \[{{f}_{2}}=\frac{3}{4}{{f}_{1}}\]

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