1.

An object, moving with a speed of \[6.25\text{ }m/s\], is decelerate data rate given by: \[\frac{\text{dv}}{\text{dt}}=\text{ -2}\text{.5}\sqrt{\text{v}}\]where v is the instantaneous speed. The time taken by the object, to come to rest, would be

A. 2s                    
B. 4s  
C. 8s                    
D. 1s
Answer» B. 4s  


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