MCQOPTIONS
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| 1. |
An object, moving with a speed of \[6.25\text{ }m/s\], is decelerate data rate given by: \[\frac{\text{dv}}{\text{dt}}=\text{ -2}\text{.5}\sqrt{\text{v}}\]where v is the instantaneous speed. The time taken by the object, to come to rest, would be |
| A. | 2s |
| B. | 4s |
| C. | 8s |
| D. | 1s |
| Answer» B. 4s | |