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An integrating factor for the differential equation \[(1+{{y}^{2}})dx-({{\tan }^{-1}}y-x)dy=0\]         [MP PET 1993]

A.                 \[{{\tan }^{-1}}y\]             
B.                 \[{{e}^{{{\tan }^{-1}}y}}\]
C.                 \[\frac{1}{1+{{y}^{2}}}\]               
D.                 \[\frac{1}{x(1+{{y}^{2}})}\]
Answer» C.                 \[\frac{1}{1+{{y}^{2}}}\]               


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