MCQOPTIONS
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| 1. |
An ideal efficient transformer has a primary power input of 10 kW. The secondary current when the transformer is on load is 25 A. If the primary: secondary turns ratio is 8 : 1, then the potential difference applied to the primary coil is |
| A. | \[\frac{{{10}^{4}}\times {{8}^{2}}}{25}V\] |
| B. | \[\frac{{{10}^{4}}\times 8}{25}V\] |
| C. | \[\frac{{{10}^{4}}}{25\times 8}V\] |
| D. | \[\frac{{{10}^{4}}}{25\times {{8}^{2}}}V\] |
| Answer» C. \[\frac{{{10}^{4}}}{25\times 8}V\] | |