MCQOPTIONS
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| 1. |
An elementary particle of mass \[m\] and charge \[+e\] is projected with velocity \[v\] at a much more massive particle of charge \[Ze,\] where \[Z>0.\]What is the closest possible approach of the incident particle [Orissa JEE 2002] |
| A. | \[\frac{Z{{e}^{2}}}{2\pi {{\varepsilon }_{0}}m{{v}^{2}}}\] |
| B. | \[\frac{Ze}{4\pi {{\varepsilon }_{0}}m{{v}^{2}}}\] |
| C. | \[\frac{Z{{e}^{2}}}{8\pi {{\varepsilon }_{0}}m{{v}^{2}}}\] |
| D. | \[\frac{Ze}{8\pi {{\varepsilon }_{0}}m{{v}^{2}}}\] |
| Answer» B. \[\frac{Ze}{4\pi {{\varepsilon }_{0}}m{{v}^{2}}}\] | |