1.

An elementary particle of mass \[m\] and charge \[+e\] is projected with velocity \[v\] at a much more massive particle of charge \[Ze,\] where \[Z>0.\]What is the closest possible approach of the incident particle                     [Orissa JEE 2002]

A.            \[\frac{Z{{e}^{2}}}{2\pi {{\varepsilon }_{0}}m{{v}^{2}}}\]
B.                                      \[\frac{Ze}{4\pi {{\varepsilon }_{0}}m{{v}^{2}}}\]
C.            \[\frac{Z{{e}^{2}}}{8\pi {{\varepsilon }_{0}}m{{v}^{2}}}\]   
D.            \[\frac{Ze}{8\pi {{\varepsilon }_{0}}m{{v}^{2}}}\]
Answer» B.                                      \[\frac{Ze}{4\pi {{\varepsilon }_{0}}m{{v}^{2}}}\]


Discussion

No Comment Found

Related MCQs