MCQOPTIONS
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| 1. |
An electron moving with the speed \[5\times {{10}^{6}}\] per sec is shooted parallel to the electric field of intensity \[1\times {{10}^{3}}N/C\]. Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of \[e=9\times {{10}^{-31}}Kg.\] charge \[=1.6\times {{10}^{-19}}C)\] [MP PMT 2003] |
| A. | 7 m |
| B. | 0.7 mm |
| C. | 7 cm |
| D. | 0.7 cm |
| Answer» D. 0.7 cm | |