MCQOPTIONS
Saved Bookmarks
| 1. |
An electron jumps from the 4th orbit to the 2nd orbit of hydrogen atom. Given the Rydberg's constant \[R={{10}^{5}}c{{m}^{-1}}\]. The frequency in Hz of the emitted radiation will be [CPMT 1976] |
| A. | \[\frac{3}{16}\times {{10}^{5}}\] |
| B. | \[\frac{3}{16}\times {{10}^{15}}\] |
| C. | \[\frac{9}{16}\times {{10}^{15}}\] |
| D. | \[\frac{3}{4}\times {{10}^{15}}\] |
| Answer» D. \[\frac{3}{4}\times {{10}^{15}}\] | |