An asteroid of mass m is approaching earth initially at a distance of$$10{{\operatorname{R}}_{e}}$$, with speed$${{v}_{i}}$$. It hits the earth with a speed $${{v}_{f}}({{\operatorname{R}}_{e}}\,\,and\,\,{{M}_{e}}$$, are radius and mass of earth), then

Question

TuteeHUB · Accepted Answer

$${{v}_{f}}^{2}={{v}_{i}}^{2}+\frac{2GM}{{{\operatorname{R}}_{e}}}\left( 1-\frac{1}{10} \right)$$

TuteeHUB · Answer

$${{v}_{f}}^{2}={{v}_{i}}^{2}+\frac{2GM}{{{M}_{e}}R}\left( 1-\frac{1}{10} \right)$$

TuteeHUB · Answer

$${{v}_{f}}^{2}={{v}_{i}}^{2}+\frac{2G{{M}_{e}}}{{{\operatorname{R}}_{e}}}\left( 1+\frac{1}{10} \right)$$

TuteeHUB · Answer

$${{v}_{f}}^{2}={{v}_{i}}^{2}+\frac{2G{{M}_{e}}}{{{\operatorname{R}}_{e}}}\left( 1-\frac{1}{10} \right)$$

1.	An asteroid of mass m is approaching earth initially at a distance of\[10{{\operatorname{R}}_{e}}\], with speed\[{{v}_{i}}\]. It hits the earth with a speed \[{{v}_{f}}({{\operatorname{R}}_{e}}\,\,and\,\,{{M}_{e}}\], are radius and mass of earth), then
A.	\[{{v}_{f}}^{2}={{v}_{i}}^{2}+\frac{2GM}{{{M}_{e}}R}\left( 1-\frac{1}{10} \right)\]
B.	\[{{v}_{f}}^{2}={{v}_{i}}^{2}+\frac{2G{{M}_{e}}}{{{\operatorname{R}}_{e}}}\left( 1+\frac{1}{10} \right)\]
C.	\[{{v}_{f}}^{2}={{v}_{i}}^{2}+\frac{2G{{M}_{e}}}{{{\operatorname{R}}_{e}}}\left( 1-\frac{1}{10} \right)\]
D.	\[{{v}_{f}}^{2}={{v}_{i}}^{2}+\frac{2GM}{{{\operatorname{R}}_{e}}}\left( 1-\frac{1}{10} \right)\]
Answer» D. \[{{v}_{f}}^{2}={{v}_{i}}^{2}+\frac{2GM}{{{\operatorname{R}}_{e}}}\left( 1-\frac{1}{10} \right)\]

An asteroid of mass m is approaching earth initially at a distance of\[10{{\operatorname{R}}_{e}}\], with speed\[{{v}_{i}}\]. It hits the earth with a speed \[{{v}_{f}}({{\operatorname{R}}_{e}}\,\,and\,\,{{M}_{e}}\], are radius and mass of earth), then

Discussion

No Comment Found

Related MCQs

Reply to Comment