MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
| 1. |
An aluminum rod (Young's modulus \[=7\times {{10}^{9}}\,N/{{m}^{2}})\] has a breaking strain of 0.2%. The minimum cross-sectional area of the rod in order to support a load of \[{{10}^{4}}\]Newton's is [MP PMT 1991] |
| A. | \[1\times {{10}^{-2}}\,{{m}^{2}}\] |
| B. | \[1.4\times {{10}^{-3}}\,{{m}^{2}}\] |
| C. | \[3.5\times {{10}^{-3}}\,{{m}^{2}}\] |
| D. | \[7.1\times {{10}^{-4}}\,{{m}^{2}}\] |
| Answer» E. | |