MCQOPTIONS
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| 1. |
An \[\alpha \]-particle of energy 5 MeV is scattered through \[180{}^\circ \] by a fixed uranium nucleus. The distance of closest approach is of the order of |
| A. | \[{{10}^{-12}}cm\] |
| B. | \[{{10}^{-10}}cm\] |
| C. | \[{{10}^{-14}}cm\] |
| D. | \[{{10}^{-15}}cm\,\] |
| Answer» B. \[{{10}^{-10}}cm\] | |