An \[\alpha \]-particle of 10 MeV collides head-on with a copper nucle – McqOptions

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1.	An \[\alpha \]-particle of 10 MeV collides head-on with a copper nucleus (Z=29) and is deflected back. Then, the minimum distance of approach between the centers of the two is:
A.	\[8.4\times {{10}^{-15}}cm\]
B.	\[8.4\times {{10}^{-15}}m\]
C.	\[4.2\times {{10}^{-15}}m\]
D.	\[4.2\times {{10}^{-15}}cm\]
Answer» C. \[4.2\times {{10}^{-15}}m\]

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