MCQOPTIONS
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MCQOPTIONS
| 1. |
According to the Stokes’ law, the rate of settling of the particles depends on the terminal settling velocity vt which isWheredp = Particle diameterρp = Density of particleρa = Density of airμa = Velocity of airP = Air pressureC = Constant |
| A. | \(\frac{{gd_p^2}}{{18{\mu _a}}}\left( {{\rho _p} - {\rho _a}} \right)\left[ {1 + \frac{{2C}}{{{d_p}P}}} \right]\) |
| B. | \(\frac{{gd_p^2}}{{18{\mu _a}}}\left( {{\rho _p} + {\rho _a}} \right)\left[ {1 - \frac{{2C}}{{{d_p}P}}} \right]\) |
| C. | \(\frac{{gd_p^2}}{{18{\mu _a}}}\left( {{\rho _p} - {\rho _a}} \right)\left[ {1 - \frac{{2C}}{{{d_p}P}}} \right]\) |
| D. | \(\frac{{gd_p^2}}{{18{\mu _a}}}\left( {{\rho _p} + {\rho _a}} \right)\left[ {1 + \frac{{2C}}{{{d_p}P}}} \right]\) |
| Answer» B. \(\frac{{gd_p^2}}{{18{\mu _a}}}\left( {{\rho _p} + {\rho _a}} \right)\left[ {1 - \frac{{2C}}{{{d_p}P}}} \right]\) | |