According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

According to parallel axis theorem, the moment of inertia of a section

1.	According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)
A.	IP = IG + Ah2
B.	IP = IG - Ah2
C.	IP = IG / Ah2
D.	IP = Ah2 / IG
Answer» B. IP = IG - Ah2