According to Newton, the viscous force acting between liquid layers of area A and velocity gradient $$\Delta v/\Delta z$$ is given by $$F=-\eta A\frac{\Delta v}{\Delta z}$$ where $$\eta $$ is constant called coefficient of viscosity. The dimension of $$\eta $$ are? [JIPMER 2001, 02]

Question

According to Newton, the viscous force acting between liquid layers of area A and velocity gradient $$\Delta v/\Delta z$$ is given by $$F=-\eta A\frac{\Delta v}{\Delta z}$$ where $$\eta $$ is constant called coefficient of viscosity. The dimension of $$\eta $$ are?                                                                                [JIPMER 2001, 02]

TuteeHUB · Accepted Answer

$$[M{{L}^{-2}}{{T}^{-2}}]$$

TuteeHUB · Answer

$$[M{{L}^{2}}{{T}^{-2}}]$$

TuteeHUB · Answer

$$[M{{L}^{-1}}{{T}^{-1}}]$$

TuteeHUB · Answer

$$[{{M}^{0}}{{L}^{0}}{{T}^{0}}]$$

1.	According to Newton, the viscous force acting between liquid layers of area A and velocity gradient \[\Delta v/\Delta z\] is given by \[F=-\eta A\frac{\Delta v}{\Delta z}\] where \[\eta \] is constant called coefficient of viscosity. The dimension of \[\eta \] are? [JIPMER 2001, 02]
A.	\[[M{{L}^{2}}{{T}^{-2}}]\]
B.	\[[M{{L}^{-1}}{{T}^{-1}}]\]
C.	\[[M{{L}^{-2}}{{T}^{-2}}]\]
D.	\[[{{M}^{0}}{{L}^{0}}{{T}^{0}}]\]
Answer» C. \[[M{{L}^{-2}}{{T}^{-2}}]\]

According to Newton, the viscous force acting between liquid layers of area A and velocity gradient \[\Delta v/\Delta z\] is given by \[F=-\eta A\frac{\Delta v}{\Delta z}\] where \[\eta \] is constant called coefficient of viscosity. The dimension of \[\eta \] are? [JIPMER 2001, 02]

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