ABC is a cyclic triangle and the bisectors of BAC, ABC and BCA meet the circle at P, Q, and R respectively. Then the angle RQP is

• A. <table><tr><td rowspan="2">90 - </td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>B</center></td></tr><tr><td style="text-align: center;">2</td></tr></table>
• B. <table><tr><td rowspan="2">90 + </td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>B</center></td></tr><tr><td style="text-align: center;">2</td></tr></table>
• C. <table><tr><td rowspan="2">90 + </td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>C</center></td></tr><tr><td style="text-align: center;">2</td></tr></table>
• D. <table><tr><td rowspan="2">90 - </td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>A</center></td></tr><tr><td style="text-align: center;">2</td></tr></table>