\[A+2B\to C+D\]. If \[-\frac{d[A]}{dt}=5\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]1, then \[-\frac{d[B]}{dt}\] is [DPMT 2005]

\[5.0\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]

\[2.5\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]

\[2.5\times 10-3mol\,{{l}^{-1}}{{s}^{-1}}\]

\[1.0\times {{10}^{-3}}mol\,{{l}^{-1}}{{s}^{-1}}\]

\[A+2B\to C+D\]. If \[-\frac{d[A]}{dt}=5\times {{10}^{-4}}mol\,{{l}^{-

1.	\[A+2B\to C+D\]. If \[-\frac{d[A]}{dt}=5\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]1, then \[-\frac{d[B]}{dt}\] is [DPMT 2005]
A.	\[2.5\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]
B.	\[5.0\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]
C.	\[2.5\times 10-3mol\,{{l}^{-1}}{{s}^{-1}}\]
D.	\[1.0\times {{10}^{-3}}mol\,{{l}^{-1}}{{s}^{-1}}\]
Answer» B. \[5.0\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]

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\[A+2B\to C+D\]. If \[-\frac{d[A]}{dt}=5\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]1, then \[-\frac{d[B]}{dt}\] is [DPMT 2005]

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