A wire in the shape of an equilateral triangle encloses an area of S sq. cm. If the same wire is bent to form of a circle. The area of the circle will be

• A.  \[\frac{\pi {{S}^{2}}}{9}\]            
• B.  \[\frac{3{{S}^{2}}}{\pi }\]
• C.  \[\frac{3S}{\pi }\]                             
• D.  \[\frac{3\sqrt{3}S}{\pi }\]