A uniform ring of mass m and radius r is placed directly above a uniform sphere of mass M and of equal radius. The centre of the ring is directly above the centre of the sphere at a distance $$r\sqrt{3}$$ as shown in the figure. The gravitational field due to the ring at a distance $$\sqrt{3}r$$is.

Question

TuteeHUB · Accepted Answer

$$\frac{Gm}{8{{r}^{2}}\sqrt{3}}$$

TuteeHUB · Answer

$$\frac{Gm}{8{{r}^{2}}}$$

TuteeHUB · Answer

$$\frac{Gm}{4{{r}^{2}}}$$

TuteeHUB · Answer

$$\sqrt{3}\frac{Gm}{8{{r}^{2}}}$$

1.	A uniform ring of mass m and radius r is placed directly above a uniform sphere of mass M and of equal radius. The centre of the ring is directly above the centre of the sphere at a distance \[r\sqrt{3}\] as shown in the figure. The gravitational field due to the ring at a distance \[\sqrt{3}r\]is.
A.	\[\frac{Gm}{8{{r}^{2}}}\]
B.	\[\frac{Gm}{4{{r}^{2}}}\]
C.	\[\sqrt{3}\frac{Gm}{8{{r}^{2}}}\]
D.	\[\frac{Gm}{8{{r}^{2}}\sqrt{3}}\]
Answer» D. \[\frac{Gm}{8{{r}^{2}}\sqrt{3}}\]

A uniform ring of mass m and radius r is placed directly above a uniform sphere of mass M and of equal radius. The centre of the ring is directly above the centre of the sphere at a distance \[r\sqrt{3}\] as shown in the figure. The gravitational field due to the ring at a distance \[\sqrt{3}r\]is.

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