MCQOPTIONS
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| 1. |
A uniform magnetic field B is acting from south to north and is of magnitude 1.5 \[Wb/{{m}^{2}}\]. If a proton having mass \[=1.7\times {{10}^{-27}}\,kg\] and charge \[=1.6\times {{10}^{-19}}\,C\] moves in this field vertically downwards with energy 5 MeV, then the force acting on it will be [Pb. PMT 2002] |
| A. | \[7.4\times {{10}^{12}}\,N\] |
| B. | \[7.4\times {{10}^{-12}}\,N\] |
| C. | \[7.4\times {{10}^{19}}\,N\] |
| D. | \[7.4\times {{10}^{-19}}\,N\] |
| Answer» C. \[7.4\times {{10}^{19}}\,N\] | |