A tower subtends angles \[\alpha ,\,2\alpha ,\,3\alpha \]respectively at points A, B and \[C\], all lying on a horizontal line through the foot of the tower. Then \[AB/BC=\] [EAMCET 2003]

\[\frac{\sin 3\alpha }{\sin 2\alpha }\]

\[\frac{\sin 2\alpha }{\sin \alpha }\]

A tower subtends angles \[\alpha ,\,2\alpha ,\,3\alpha \]respectively

1.	A tower subtends angles \[\alpha ,\,2\alpha ,\,3\alpha \]respectively at points A, B and \[C\], all lying on a horizontal line through the foot of the tower. Then \[AB/BC=\] [EAMCET 2003]
A.	\[\frac{\sin 3\alpha }{\sin 2\alpha }\]
B.	\[1+2\cos 2\alpha \]
C.	\[2+\cos 3\alpha \]
D.	\[\frac{\sin 2\alpha }{\sin \alpha }\]
Answer» C. \[2+\cos 3\alpha \]

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A tower subtends angles \[\alpha ,\,2\alpha ,\,3\alpha \]respectively at points A, B and \[C\], all lying on a horizontal line through the foot of the tower. Then \[AB/BC=\] [EAMCET 2003]

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