MCQOPTIONS
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| 1. |
A torque of \[{{10}^{-\,5}}\,Nm\] is required to hold a magnet at \[90{}^\circ \] with the horizontal component H of the earth's magnetic field. The torque to hold it at \[30{}^\circ \] will be |
| A. | \[5\times {{10}^{-6}}\,Nm\] |
| B. | 5 Nm |
| C. | \[\frac{1}{3}\times {{10}^{-5}}\,Nm\] |
| D. | \[5\sqrt{3}\times {{10}^{-6}}\,Nm\] |
| Answer» B. 5 Nm | |