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A substance \[{{C}_{4}}{{H}_{10}}O\] yields on oxidation a compound, \[{{C}_{4}}{{H}_{8}}O\] which gives an oxime and a positive iodoform test. The original substance on treatment with cone. \[{{H}_{2}}S{{O}_{4}}\] gives \[{{C}_{2}}{{H}_{8}}\] The structure of the compound is

A. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH\]
B. \[C{{H}_{3}}CHOHC{{H}_{2}}C{{H}_{3}}\]
C. \[{{\left( C{{H}_{3}} \right)}_{3}}COH\]
D. \[C{{H}_{3}}C{{H}_{2}}-O-C{{H}_{2}}C{{H}_{3}}\]
Answer» C. \[{{\left( C{{H}_{3}} \right)}_{3}}COH\]


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