A string is under tension so that its length is increased by \[1/n\] t – McqOptions

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1.	A string is under tension so that its length is increased by \[1/n\] times its original length. The ratio of fundamental frequency of longitudinal vibrations and transverse vibrations will be
A.	\[1:n\]
B.	\[{{n}^{2}}:1\]
C.	\[\sqrt{n}:1\]
D.	\[n:1\]
Answer» D. \[n:1\]

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