A straight chain hydrocarbon has the molecular formula $${{C}_{8}}{{H}_{10}}$$. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $$s{{p}^{3}},\text{ }s{{p}^{2}},\text{ }s{{p}^{2}}\text{, }s{{p}^{3}},\text{ }s{{p}^{2}},\text{ }s{{p}^{2}},\text{ }sp$$ and $$sp$$. The structural formula of the hydrocarbon would be [CBSE PMT 1992]

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$$C{{H}_{3}}-C\equiv C-C{{H}_{2}}-CH=CH-CH=C{{H}_{2}}$$

TuteeHUB · Answer

$$C{{H}_{3}}-C{{H}_{2}}-CH=CH-C{{H}_{2}}-C\equiv C-CH=C{{H}_{2}}$$

TuteeHUB · Answer

$$C{{H}_{3}}-CH=CH-C{{H}_{2}}-C\equiv C-CH=C{{H}_{2}}$$

TuteeHUB · Answer

$$C{{H}_{3}}-CH=CH-C{{H}_{2}}-CH=CH-C\equiv CH$$

1.	A straight chain hydrocarbon has the molecular formula \[{{C}_{8}}{{H}_{10}}\]. The hybridisation for the carbon atoms from one end of the chain to the other are respectively \[s{{p}^{3}},\text{ }s{{p}^{2}},\text{ }s{{p}^{2}}\text{, }s{{p}^{3}},\text{ }s{{p}^{2}},\text{ }s{{p}^{2}},\text{ }sp\] and \[sp\]. The structural formula of the hydrocarbon would be [CBSE PMT 1992]
A.	\[C{{H}_{3}}-C\equiv C-C{{H}_{2}}-CH=CH-CH=C{{H}_{2}}\]
B.	\[C{{H}_{3}}-C{{H}_{2}}-CH=CH-C{{H}_{2}}-C\equiv C-CH=C{{H}_{2}}\]
C.	\[C{{H}_{3}}-CH=CH-C{{H}_{2}}-C\equiv C-CH=C{{H}_{2}}\]
D.	\[C{{H}_{3}}-CH=CH-C{{H}_{2}}-CH=CH-C\equiv CH\]
Answer» E.

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