MCQOPTIONS
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| 1. |
A stone projected with a velocity \[u\] at an angle \[\theta \] With the horizontal reaches maximum height \[{{H}_{1}}\] When it is projected with velocity u at an angle \[(\frac{\pi }{2}-\theta )\] with the horizontal, it reaches maximum height \[{{H}_{2}}\]. The relation between the horizontal range R of the projectile, \[{{H}_{1}}\]and \[{{H}_{2}}\]is |
| A. | \[R=4\sqrt{{{H}_{1}}{{H}_{2}}}\] |
| B. | \[R=\,4({{H}_{1}}-{{H}_{2}})\] |
| C. | \[R=\,4({{H}_{1}}+{{H}_{2}})\] |
| D. | \[R=\,\frac{{{H}^{2}}_{1}}{{{H}^{2}}_{2}}\] |
| Answer» B. \[R=\,4({{H}_{1}}-{{H}_{2}})\] | |