A stone dropped from a building of height h and it reaches after t seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity u and they reach the earth surface after $${{t}_{1}}$$ and $${{t}_{2}}$$ seconds, respectively, then

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TuteeHUB · Accepted Answer

$$t_{1}^{2}=t_{2}^{2}$$

TuteeHUB · Answer

$$t={{t}_{1}}-{{t}_{2}}$$

TuteeHUB · Answer

$$t=\frac{{{t}_{1}}+{{t}_{2}}}{2}$$

TuteeHUB · Answer

$$t=\sqrt{{{t}_{1}}{{t}_{2}}}$$

1.	A stone dropped from a building of height h and it reaches after t seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity u and they reach the earth surface after \[{{t}_{1}}\] and \[{{t}_{2}}\] seconds, respectively, then
A.	\[t={{t}_{1}}-{{t}_{2}}\]
B.	\[t=\frac{{{t}_{1}}+{{t}_{2}}}{2}\]
C.	\[t=\sqrt{{{t}_{1}}{{t}_{2}}}\]
D.	\[t_{1}^{2}=t_{2}^{2}\]
Answer» D. \[t_{1}^{2}=t_{2}^{2}\]

A stone dropped from a building of height h and it reaches after t seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity u and they reach the earth surface after \[{{t}_{1}}\] and \[{{t}_{2}}\] seconds, respectively, then

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