A_STEEL_ROD_(K_=_30_W/M_DEGREE)_1_CM_IN_DIAMETER_AND_5_CM_LONG_PROTRUDES_FROM_A_WALL_WHICH_IS_MAINTAINED_AT_10_DEGREE_CELSIUS._THE_ROD_IS_INSULATED_AT_ITS_TIP_AND_IS_EXPOSED_TO_AN_ENVIRONMENT_WITH_H_=_50_W/M2_DEGREE_AND_T_A_=_30_DEGREE_CELSIUS._CALCULATE_THE_RATE_OF_HEAT_DISSIPATION?$

A_STEEL_ROD_(K_=_30_W/M_DEGREE)_1_CM_IN_DIAMETER_AND_5_CM_LONG_PROTRUD

1.	A_STEEL_ROD_(K_=_30_W/M_DEGREE)_1_CM_IN_DIAMETER_AND_5_CM_LONG_PROTRUDES_FROM_A_WALL_WHICH_IS_MAINTAINED_AT_10_DEGREE_CELSIUS._THE_ROD_IS_INSULATED_AT_ITS_TIP_AND_IS_EXPOSED_TO_AN_ENVIRONMENT_WITH_H_=_50_W/M2_DEGREE_AND_T_A_=_30_DEGREE_CELSIUS._CALCULATE_THE_RATE_OF_HEAT_DISSIPATION?$
A.	2.658 W
B.	3.658 W
C.	4.658 W
D.	5.658 W
Answer» C. 4.658 W

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A_STEEL_ROD_(K_=_30_W/M_DEGREE)_1_CM_IN_DIAMETER_AND_5_CM_LONG_PROTRUDES_FROM_A_WALL_WHICH_IS_MAINTAINED_AT_10_DEGREE_CELSIUS._THE_ROD_IS_INSULATED_AT_ITS_TIP_AND_IS_EXPOSED_TO_AN_ENVIRONMENT_WITH_H_=_50_W/M2_DEGREE_AND_T_A_=_30_DEGREE_CELSIUS._CALCULATE_THE_RATE_OF_HEAT_DISSIPATION?$

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