MCQOPTIONS
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| 1. |
A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O, and PO = OQ. The distance PO is equal to [IIT JEE 1998; DPMT 2000] |
| A. | 5 R |
| B. | 3 R |
| C. | 2 R |
| D. | 1.5 R |
| Answer» B. 3 R | |