1.

A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O, and PO = OQ. The distance PO is equal to                             [IIT JEE 1998; DPMT 2000]

A.            5 R 
B.            3 R
C.            2 R 
D.            1.5 R
Answer» B.            3 R


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