1.

A source of light is placed at a distance of 50 cm from a photocell and the stopping potential is found to be \[{{V}_{0}}\]. If the distance between the light source and photocell is made 25 cm, the new stopping potential will be

A. \[2{{V}_{0}}\]  
B. \[{{V}_{0}}/2\]
C. \[{{V}_{0}}\]   
D. \[4{{V}_{0}}\]
Answer» D. \[4{{V}_{0}}\]


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