A solution of the equation \[{{\tan }^{-1}}(1+x)\] \[+{{\tan }^{-1}}(1-x)\] \[=\frac{\pi }{2}\] is [Karnataka CET 1993]

A solution of the equation \[{{\tan }^{-1}}(1+x)\] \[+{{\tan }^{-1}}(1

1.	A solution of the equation \[{{\tan }^{-1}}(1+x)\] \[+{{\tan }^{-1}}(1-x)\] \[=\frac{\pi }{2}\] is [Karnataka CET 1993]
A.	\[x=1\]
B.	\[x=-1\]
C.	\[x=0\]
D.	\[x=\pi \]
Answer» D. \[x=\pi \]

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A solution of the equation \[{{\tan }^{-1}}(1+x)\] \[+{{\tan }^{-1}}(1-x)\] \[=\frac{\pi }{2}\] is [Karnataka CET 1993]

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