A small block slides without friction down an inclined plane starting from rest. Let \[{{S}_{n}}\]be the distance travelled from time \[t=n-1\] to \[t=n.\] Then \[\frac{{{S}_{n}}}{{{S}_{n+1}}}\] is [IIT-JEE (Screening) 2004]

• A.                              \[\frac{2n-1}{2n}\]                
• B.                         \[\frac{2n+1}{2n-1}\]          
• C.                         \[\frac{2n-1}{2n+1}\]                     
• D.                         \[\frac{2n}{2n+1}\]