 
			 
			MCQOPTIONS
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				| 1. | A signal has \(FT\;x\left( t \right)\mathop \leftrightarrow \limits^{FT} X\left( {j\omega } \right) = {e^{ - j\omega }}\left| \omega \right|{e^{ - 2\left| \omega \right|}}\) Without determining x(t), use the scaling property to find the FT representation of y(t) = x( - 2t). | 
| A. | \(Y\left( {j\omega } \right) = \left( {\frac{1}{2}} \right){e^{\frac{{j\omega }}{2}}}\left| {\frac{\omega }{2}} \right|{e^{\left| \omega \right|}}\) | 
| B. | \(Y\left( {j\omega } \right) = \left( {\frac{1}{2}} \right){e^{\frac{{j\omega }}{2}}}\left| {\frac{\omega }{2}} \right|{e^{2\left| \omega \right|}}\) | 
| C. | \(Y\left( {j\omega } \right) = \left( {\frac{1}{2}} \right){e^{\frac{{j\omega }}{2}}}\left| {\frac{\omega }{2}} \right|{e^{ - 2\left| \omega \right|}}\) | 
| D. | \(Y\left( {j\omega } \right) = \left( {\frac{1}{2}} \right){e^{\frac{{j\omega }}{2}}}\left| {\frac{\omega }{2}} \right|{e^{ - \left| \omega \right|}}\) | 
| Answer» E. | |