A set of n identical cubical blocks lies at rest parallel to each other along a line on a smooth horizontal surface. The separation between the near surfaces of any two adjacent blocks is L. The block at one end is given a speed v towards the next one at time $$t=0$$. All collisions are completely inelastic, then [IIT 1995]

Question

A set of n identical cubical blocks lies at rest parallel to each other along a line on a smooth horizontal surface. The separation between the near surfaces of any two adjacent blocks is L. The block at one end is given a speed v towards the next one at time $$t=0$$. All collisions are completely inelastic, then                          [IIT 1995]

TuteeHUB · Accepted Answer

The centre of mass of the system will have a final speed v

TuteeHUB · Answer

The last block starts moving at $$t=\frac{(n-1)L}{v}$$

TuteeHUB · Answer

The last block starts moving at $$t=\frac{n(n-1)L}{2v}$$

TuteeHUB · Answer

The centre of mass of the system will have a final speed  $$\frac{v}{n}$$

1.	A set of n identical cubical blocks lies at rest parallel to each other along a line on a smooth horizontal surface. The separation between the near surfaces of any two adjacent blocks is L. The block at one end is given a speed v towards the next one at time \[t=0\]. All collisions are completely inelastic, then [IIT 1995]
A.	The last block starts moving at \[t=\frac{(n-1)L}{v}\]
B.	The last block starts moving at \[t=\frac{n(n-1)L}{2v}\]
C.	The centre of mass of the system will have a final speed v
D.	The centre of mass of the system will have a final speed \[\frac{v}{n}\]
Answer» C. The centre of mass of the system will have a final speed v

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