MCQOPTIONS
Saved Bookmarks
| 1. |
A satellite moves eastwards very near the surface of the Earth in equatorial plane with speed (\[{{v}_{0}}\]). Another satellite moves at the same height with the same speed in the equatorial plane but westwards. If \[R\]= radius of the Earth and \[\omega \]) be its angular speed of the Earth about its own axis. Then find the approximate difference in the two time period as observed on the Earth. |
| A. | \[\frac{4\pi \omega {{R}^{2}}}{{{v}_{0}}^{2}+{{R}^{2}}{{\omega }^{2}}}\] |
| B. | \[\frac{2\pi \omega {{R}^{2}}}{{{v}_{0}}^{2}-{{R}^{2}}{{\omega }^{2}}}\] |
| C. | \[\frac{4\pi \omega {{R}^{2}}}{{{v}_{0}}^{2}-{{R}^{2}}{{\omega }^{2}}}\] |
| D. | \[\frac{2\pi \omega {{R}^{2}}}{{{v}_{0}}^{2}+{{R}^{2}}{{\omega }^{2}}}\] |
| Answer» D. \[\frac{2\pi \omega {{R}^{2}}}{{{v}_{0}}^{2}+{{R}^{2}}{{\omega }^{2}}}\] | |