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1. |
A reaction rate constant is given by \[k=1.2\times {{10}^{14}}{{e}^{-25000/RT}}se{{c}^{-1}}\]. It means |
A. | log k versus log T will give a straight line with a slope as \[-25000\] |
B. | log k versus T will give a straight line with slope as 25000 |
C. | log k versus 1/T will give a straight line with slope as \[-25000/R\] |
D. | log k versus 1/T will give a straight line |
Answer» D. log k versus 1/T will give a straight line | |