1.

A reaction rate constant is given by \[k=1.2\times {{10}^{14}}{{e}^{-25000/RT}}se{{c}^{-1}}\]. It means

A. log k versus log T will give a straight line with a slope as \[-25000\]
B. log k versus T will give a straight line with slope as 25000
C. log k versus 1/T will give a straight line with slope as \[-25000/R\]
D. log k versus 1/T will give a straight line
Answer» D. log k versus 1/T will give a straight line


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